2c^2-5c-12=0

Solution for 2c^2-5c-12=0 equation:

Simplifying
2c2 + -5c + -12 = 0

Reorder the terms:
-12 + -5c + 2c2 = 0

Solving
-12 + -5c + 2c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-3 + -2c)(4 + -1c) = 0

Subproblem 1
Set the factor '(-3 + -2c)' equal to zero and attempt to solve:

Simplifying
-3 + -2c = 0

Solving
-3 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -2c = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -2c = 0 + 3
-2c = 0 + 3

Combine like terms: 0 + 3 = 3
-2c = 3

Divide each side by '-2'.
c = -1.5

Simplifying
c = -1.5
Subproblem 2
Set the factor '(4 + -1c)' equal to zero and attempt to solve:

Simplifying
4 + -1c = 0

Solving
4 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1c = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1c = 0 + -4
-1c = 0 + -4

Combine like terms: 0 + -4 = -4
-1c = -4

Divide each side by '-1'.
c = 4

Simplifying
c = 4
Solution
c = {-1.5, 4}